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Proof step 26 from proof fillsgn-short (previous step)

fillsgn(2, int2bytes(bytes2int(bytes))) = bytes, bytes = bytes.first ', 1 ≤ # fillsgn(1, int2bytes(bytes2int(bytes))) ⊦ fillsgn(1, int2bytes(bytes2int(bytes))) = [], bytes = []

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 27:
bytes = by + bytes0, fillsgn(2, int2bytes(bytes2int(bytes))) = bytes, bytes = by ', 1 ≤ # fillsgn(1, int2bytes(bytes2int(bytes))) ⊦ fillsgn(1, int2bytes(bytes2int(bytes))) = [], bytes = []

Rule argument

seq: bytes ≠ [] ⊦ by = bytes.first ∧ bytes0 = bytes.rest ↔ bytes = by + bytes0 subst: [bytes, by, bytes0] → [bytes, by, bytes0] rotate: T spec: list-data inst: bytelist name: elim-list-c

Additional information

Used simplifier rules: bytes ≠ [] ⊦ by = bytes.first ∧ bytes0 = bytes.rest ↔ bytes = by + bytes0; (elim) Used terms: bytes, by, bytes0