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Proof step 7 from proof fillsgn-short (previous step)

# bytes ≤ # fillsgn(# bytes, int2bytes(bytes2int(bytes))), 2 ≤ # bytes, 2 ≤ # fillsgn(# bytes, int2bytes(bytes2int(bytes))) ⊦ bytes = [], fillsgn(2, int2bytes(bytes2int(bytes))) = bytes ↔ 2 < # bytes → int2bytes(bytes2int(bytes)) = bytes, fillsgn(# bytes, int2bytes(bytes2int(bytes))) = []

User applied rule cut formula

And obtained the following new goals

Proof step 8:
2 < # bytes, # bytes ≤ # fillsgn(# bytes, int2bytes(bytes2int(bytes))), 2 ≤ # bytes, 2 ≤ # fillsgn(# bytes, int2bytes(bytes2int(bytes))) ⊦ bytes = [], fillsgn(2, int2bytes(bytes2int(bytes))) = bytes ↔ 2 < # bytes → int2bytes(bytes2int(bytes)) = bytes, fillsgn(# bytes, int2bytes(bytes2int(bytes))) = []
Proof step 17:
# bytes ≤ # fillsgn(# bytes, int2bytes(bytes2int(bytes))), 2 ≤ # bytes, 2 ≤ # fillsgn(# bytes, int2bytes(bytes2int(bytes))) ⊦ 2 < # bytes, bytes = [], fillsgn(2, int2bytes(bytes2int(bytes))) = bytes ↔ 2 < # bytes → int2bytes(bytes2int(bytes)) = bytes, fillsgn(# bytes, int2bytes(bytes2int(bytes))) = []

Rule argument

fma: 2 < # bytes

Additional information

Used formulas: 2 < # bytes