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Proof step 123 from proof fix-bits2bytes-01 (previous step)

# bits = m * 8 + n0, n0 < 8, m < n, 1 + m < n ⊦ n - 1 + m = 0, mklist(false, 8 - n0) + bits = [], n * 8 = # bits, bits = [], n0 = 0, mklist(i2b(0), n - 1 + m) + bits2bytes(bits) = mklist(i2b(0), n - 1 + m) + bits2bytes(mklist(false, 8 - n0) + bits), bits.first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 124:
# bits = m * 8 + n0, n0 < 8, m < n, 1 + m < n ⊦ mklist(false, 8 - n0) + bits = [], n * 8 = # bits, bits = [], n0 = 0, bits2bytes(bits) = bits2bytes(mklist(false, 8 - n0) + bits), bits.first

Rule argument

Additional information

Used simplifier rules: ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ bytes + bytes0 = bytes + bytes1 ↔ bytes0 = bytes1;% ⊦ n < m → m - n ≠ 0;% ⊦ m + n = n + m;