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Proof step 132 from proof fix-bits2bytes-01 (previous step)

n * 8 = # bits, # bits2bytes(bits) < n ⊦ bits = [], bits.first

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 133:
⊦ # bits % 8 = 0 ∧ bits ≠ [] → # bits2bytes(bits) = # bits / 8

Rule argument

name: bits2bytes-len-01 rotate: F subst: [bits] → [bits]

Additional information

Used simplifier rules: n ≠ 0 ⊦ (m * n) % n = 0;% ⊦ m0 * m * n = (m0 * m) * n;% ⊦ m * n = n * m;%n ≠ 0 ⊦ (m * n) / n = m;% ⊦ ¬ n < n; Used terms: bits