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Proof step 137 from proof fix-bits2bytes-01 (previous step)

# bits % 8 = 0 ∧ bits ≠ [], # bits % 8 = 0, # bits < 8 * n, # bits / 8 < n ⊦ n * 8 = # bits, bits = [], mklist(i2b(0), n - # bits / 8) = bits2bytes(mklist(false, n * 8 - # bits)), bits.first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 138:
# bits % 8 = 0, # bits / 8 < n ⊦ n * 8 = # bits, mklist(i2b(0), n - # bits / 8) = bits2bytes(mklist(false, n * 8 - # bits)), bits = [], bits.first

Rule argument

Additional information

Used simplifier rules: ⊦ m * n = n * m;% ⊦ m0 * m * n = (m0 * m) * n;%n ≠ 0 ⊦ m / n < n0 → m < n0 * n;