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Proof step 146 from proof fix-bits2bytes-01 (previous step)

n0 ≤ n, # bits = n0 * 8, n0 < n ⊦ bits = [], mklist(i2b(0), n - n0) = bits2bytes(mklist(false, (n - n0) * 8)), n = n0, bits.first, ((n - n0) * 8) % 8 = 0 ∧ n ≠ n0 + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 147:
# bits = n0 * 8 ⊦ i2b(0) ' = bits2bytes(false ' + false ' + false ' + false ' + false ' + false ' + false ' + false '), bits = [], bits.first

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ m;% ⊦ ¬ m < n ↔ n ≤ m;% ⊦ m < n + 1 ↔ ¬ n < m;% ⊦ m + n ≤ m + n0 ↔ n ≤ n0;% ⊦ m = m + n ↔ n = 0;% ⊦ m < n ∧ n = n0 → m < n0; (forward)% ⊦ m = n + 1 ∧ n < n0 → m ≤ n0; (forward)% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + [] = bits;% ⊦ mklist(boolvar, 0) = [];%n ≠ 0 ⊦ mklist(false, (* n)) = false ' + mklist(false, n -1);% ⊦ mklist(by, 1) = by ';% ⊦ m + 1 = n → n - m = 1;% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m * n = n * m;% ⊦ m0 * m * n = (m0 * m) * n;%n ≠ 0 ⊦ (m * n) % n = 0;% ⊦ m ≠ n → (m ≤ n ↔ m < n);