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Proof step 165 from proof fix-bits2bytes-01 (previous step)

n - n0 = 1, # bits = n0 * 8, n0 + 1 < n, n0 < n ⊦ n = n0, bits = [], bits.first

User applied rule insert elim lemma

And closed the goal!

Rule argument

seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [n, n0, n1] rotate: T spec: nat inst: name: elim-sub

Additional information

Used simplifier rules: ⊦ m < n → ¬ n < m;% ⊦ ¬ m ≤ n ↔ n < m;% ⊦ m = m + n ↔ n = 0;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n = n + m;% ⊦ m < n → m ≤ n;% ⊦ m + n < m + n0 ↔ n < n0;%n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: n, n0, n1