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Proof step 169 from proof fix-bits2bytes-01 (previous step)

n - n0 ≠ 0, ((n - n0 - 1) * 8) % 8 = 0, # bits = n0 * 8, n0 < n, n0 + 1 < n, 8 ≤ (n - n0) * 8 ⊦ bits = [], n = n0, mklist(i2b(0), n - n0) = i2b(0) ' + mklist(i2b(0), ((n - n0 - 1) * 8) / 8), n - n0 = 1, bits.first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 170:
# bits = n0 * 8, n0 < n, n0 + 1 < n, 8 ≤ (n - n0) * 8 ⊦ n - n0 = 1, bits = [], n = n0, mklist(i2b(0), n - n0) = i2b(0) ' + mklist(i2b(0), n - n0 - 1), bits.first

Rule argument

Additional information

Used simplifier rules: ⊦ n < m → m - n ≠ 0;%n ≠ 0 ⊦ (m * n) / n = m;% ⊦ m * n = n * m;% ⊦ m0 * m * n = (m0 * m) * n;%n ≠ 0 ⊦ (m * n) % n = 0;