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Proof step 252 from proof fix-bits2bytes-01 (previous step)

n0 ≤ n, # bits = n0 * 8, n0 < n, bits.first ⊦ n = n0, mklist(i2b(~1), n - n0) = bits2bytes(mklist(true, (n - n0) * 8)), bits = [], ((n - n0) * 8) % 8 = 0 ∧ (n - n0) * 8 ≠ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 253:
(n - n0) * 8 = 0, # bits = n0 * 8, bits.first, n0 < n ⊦ n = n0, bits = [], mklist(i2b(~1), n - n0) = bits2bytes([])

Rule argument

Additional information

Used simplifier rules: ⊦ mklist(boolvar, 0) = [];% ⊦ m * n = n * m;% ⊦ m0 * m * n = (m0 * m) * n;%n ≠ 0 ⊦ (m * n) % n = 0;% ⊦ m ≠ n → (m ≤ n ↔ m < n);