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Proof step 255 from proof fix-bits2bytes-01 (previous step)

(n * 8 - n0 * 8) % 8 = 0 ∧ n * 8 - n0 * 8 ≠ 0, # bits = n0 * 8, bits.first, n0 < n ⊦ bits = [], mklist(i2b(~1), n - n0) = mklist(i2b(~1), (n * 8 - n0 * 8) / 8), n = n0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 256:
(n * 8 - n0 * 8) % 8 = 0, # bits = n0 * 8, bits.first, n0 < n ⊦ n = n0, n * 8 - n0 * 8 = 0, bits = [], n - n0 = (n * 8 - n0 * 8) / 8

Rule argument

Additional information

Used simplifier rules: ⊦ mklist(by, m) = mklist(by, n) ↔ m = n;