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Proof step 29 from proof fix-bits2bytes-01 (previous step)

¬ # bits % 8 ≠ 0, # bits = 8 * m + n0, n0 < 8, # bits ≤ 8 * m + 8, # bits2bytes(bits) ≤ m ⊦ bits = [], n0 = 0, fix(m + 1, bits2bytes(bits)) = bits2bytes(mklist(bits.first, 8 * m + 8 - # bits) + bits)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
# bits = 8 * m + n0, # bits % 8 = 0, # bits2bytes(bits) ≤ m, # bits ≤ 8 * m + 8, n0 < 8 ⊦ fix(m + 1, bits2bytes(bits)) = bits2bytes(mklist(bits.first, 8 * m + 8 - # bits) + bits), n0 = 0, bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ m * n = n * m;