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Proof step 33 from proof fix-bits2bytes-01 (previous step)

# bits2bytes(bits) ≥ m + 1, # bits = 8 * m + n0, n0 < 8, # bits ≤ 8 * m + 8 ⊦ bits = [], n0 = 0, lastn(m + 1, bits2bytes(bits)) = bits2bytes(mklist(bits.first, 8 * m + 8 - # bits) + bits)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 34:
# bits = 8 * m + n0, m < # bits2bytes(bits), # bits ≤ 8 * m + 8, n0 < 8 ⊦ lastn(m + 1, bits2bytes(bits)) = bits2bytes(mklist(bits.first, 8 * m + 8 - # bits) + bits), n0 = 0, bits = []

Rule argument

Additional information

Used simplifier rules: bits2bytes-empty: ⊦ bits2bytes(bits) ≠ [];% ⊦ # bytes = 0 ↔ bytes = [];% ⊦ m < n → n ≠ 0; (forward)% ⊦ m * n = n * m;% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + 1 ≤ n ↔ m < n;% ⊦ n ≥ m ↔ m ≤ n;