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Proof step 39 from proof fix-bits2bytes-01 (previous step)

¬ # bits % 8 ≠ 0, # bits = 8 * m + n0, m < # bits2bytes(bits), # bits ≤ 8 * m + 8, n0 < 8, m + 1 < # bits2bytes(bits) ⊦ lastn(m + 1, bits2bytes(bits)) = bits2bytes(mklist(bits.first, 8 * m + 8 - # bits) + bits), n0 = 0, bits = [], m + 1 = # bits2bytes(bits)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 40:
# bits = 8 * m + n0, # bits % 8 = 0, m + 1 < # bits2bytes(bits), n0 < 8, # bits ≤ 8 * m + 8, m < # bits2bytes(bits) ⊦ m + 1 = # bits2bytes(bits), bits = [], n0 = 0, lastn(m + 1, bits2bytes(bits)) = bits2bytes(mklist(bits.first, 8 * m + 8 - # bits) + bits)

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m * n = n * m;