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Proof step 63 from proof fix-bits2bytes-01 (previous step)

¬ # bits2bytes(bits) ≥ n0, # bits = 8 * n0 ⊦ n0 = 0, bits = [], fix(n0, bits2bytes(bits)) = bits2bytes(bits)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 64:
# bits = 8 * n0, # bits2bytes(bits) < n0 ⊦ fix(n0, bits2bytes(bits)) = bits2bytes(bits), bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (forward)% ⊦ m < n → n ≠ 0;% ⊦ ¬ m ≤ n ↔ n < m;% ⊦ n ≥ m ↔ m ≤ n;