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Proof step 66 from proof fix-bits2bytes-01 (previous step)

# bits2bytes(bits) ≥ n0, # bits = 8 * n0 ⊦ n0 = 0, bits = [], lastn(n0, bits2bytes(bits)) = bits2bytes(bits)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 67:
# bits = 8 * n0, n0 ≤ # bits2bytes(bits) ⊦ n0 = 0, bits = [], lastn(n0, bits2bytes(bits)) = bits2bytes(bits)

Rule argument

Additional information

Used simplifier rules: ⊦ n ≥ m ↔ m ≤ n;