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Proof step 7 from proof fix-bits2bytes-01 (previous step)

¬(# bits2bytes(bits) < n ∧ 0 ≤ bytes2int(bits2bytes(bits))), # bits ≤ 8 * n ⊦ n = 0, bits = [], fix(n, bits2bytes(bits)) = bits2bytes(mklist(bits.first, n * 8 - # bits) + bits), ¬ n ≤ # bits2bytes(bits) ∧ bits.first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
# bits ≤ 8 * n ⊦ n = 0, bits = [], fix(n, bits2bytes(bits)) = bits2bytes(mklist(bits.first, n * 8 - # bits) + bits), ¬ n ≤ # bits2bytes(bits) ∧ bits.first, ¬ n ≤ # bits2bytes(bits) ∧ ¬ bits.first

Rule argument

Additional information

Used simplifier rules: bits2int-pos: ⊦ bits ≠ [] → (0 ≤ bytes2int(bits2bytes(bits)) ↔ ¬ bits.first);% ⊦ ¬ m < n ↔ n ≤ m;