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Proof step 77 from proof fix-bits2bytes-01 (previous step)

n * 8 ≠ # bits, # bits2bytes(bits) < n, # bits ≤ 8 * n ⊦ mklist(i2b(0), n - # bits2bytes(bits)) + bits2bytes(bits) = bits2bytes(mklist(false, n * 8 - # bits) + bits), bits = [], bits.first, # bits % 8 = 0 ∧ n * 8 ≠ # bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 78:
# bits < 8 * n, # bits2bytes(bits) < n ⊦ # bits % 8 = 0, n * 8 = # bits, bits = [], mklist(i2b(0), n - # bits2bytes(bits)) + bits2bytes(bits) = bits2bytes(mklist(false, n * 8 - # bits) + bits), bits.first

Rule argument

Additional information

Used simplifier rules: ⊦ m0 * m * n = (m0 * m) * n;% ⊦ m < n → n ≠ 0;% ⊦ m0 * m = 0 ↔ m0 = 0 ∨ m = 0;% ⊦ m < n → n ≠ 0; (forward)% ⊦ m ≠ n → (m ≤ n ↔ m < n);% ⊦ m * n = n * m;