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Proof step 17 from proof fix-bits2bytes (previous step)

# bits = m * 8 + n0 ∧ n0 < 8 ∧ 8 ≠ 0, # bits ≤ 8 * (n - 1), n ≤ m + 1 ⊦ n0 = 0, fix(n, bits2bytes(bits)) = bits2bytes(fillsgn(n * 8, bits)), n = 0, bits = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
# bits = m * 8 + n0, n ≤ m + 1, # bits ≤ 8 * (n - 1), n0 < 8 ⊦ bits = [], n = 0, fix(n, bits2bytes(bits)) = bits2bytes(fillsgn(n * 8, bits)), n0 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (forward)