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Proof step 23 from proof fix-bits2bytes (previous step)

# bits % 8 = 0 ∧ bits ≠ [], n ≤ # bits / 8, # bits ≤ 8 * (n - 1) ⊦ bits = [], n = 0, fix(n, bits2bytes(bits)) = bits2bytes(fillsgn(n * 8, bits))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information