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Proof step 26 from proof fix-bits2bytes (previous step)

# bits2bytes(bits) < n ∧ 0 ≤ bytes2int(bits2bytes(bits)), # bits ≤ 8 * (n - 1) ⊦ bits = [], n = 0, mklist(i2b(0), n - # bits2bytes(bits)) + bits2bytes(bits) = bits2bytes(fillsgn(n * 8, bits)), ¬ n ≤ # bits2bytes(bits) ∧ bits.first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 27:
# bits2bytes(bits) < n, # bits ≤ 8 * (n - 1) ⊦ mklist(i2b(0), n - # bits2bytes(bits)) + bits2bytes(bits) = bits2bytes(fillsgn(n * 8, bits)), bits = [], bits.first

Rule argument

Additional information

Used simplifier rules: bits2int-pos: ⊦ bits ≠ [] → (0 ≤ bytes2int(bits2bytes(bits)) ↔ ¬ bits.first);% ⊦ m < n → n ≠ 0; (forward)% ⊦ m < n → (n ≤ m ↔ false);% ⊦ m < n → n ≠ 0;