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Proof step 86 from proof fix-bits2bytes (previous step)

# bits2bytes(bits) < n ∧ bytes2int(bits2bytes(bits)) < 0, # bits ≤ 8 * (n - 1) ⊦ bits = [], n = 0, mklist(i2b(~1), n - # bits2bytes(bits)) + bits2bytes(bits) = bits2bytes(fillsgn(n * 8, bits))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 87:
bits.first, # bits2bytes(bits) < n, # bits ≤ 8 * (n - 1) ⊦ mklist(i2b(~1), n - # bits2bytes(bits)) + bits2bytes(bits) = bits2bytes(fillsgn(n * 8, bits)), bits = []

Rule argument

Additional information

Used simplifier rules: bits2int-neg: ⊦ bits ≠ [] → (bytes2int(bits2bytes(bits)) < 0 ↔ bits.first);% ⊦ m < n → n ≠ 0; (forward)% ⊦ m < n → n ≠ 0;