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Proof step 10 from proof fix-butlast-longer (previous step)

1 < # bytes, # bytes < n ⊦ bytes = [], # bytes = 1, fillsgn(n + 1, bytes).butlast = fillsgn(n, bytes).first ' + fillsgn(n, bytes).butlast

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
# bytes < n ⊦ bytes = [], # bytes = 1, fillsgn(n + 1, bytes).butlast = fillsgn(n, bytes).first ' + fillsgn(n, bytes).butlast

Rule argument

Additional information

Used simplifier rules: ⊦ # bytes = 0 ↔ bytes = [];% ⊦ 1 < m ↔ ¬(m = 0 ∨ m = 1);