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Proof step 17 from proof fix-butlast (previous step)

# bytes ≤ n ⊦ fillsgn(n, bytes.butlast) = fillsgn(n + 1, bytes).butlast, # bytes = 1, bytes = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 18:
⊦ 1 < # bytes → fillsgn(n, bytes.butlast) = fillsgn(n + 1, bytes).butlast

Rule argument

name: fillsgn-butlast rotate: F subst: [bytes, n] → [bytes, n]

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ 1 < m ↔ ¬(m = 0 ∨ m = 1);% ⊦ # bytes = 0 ↔ bytes = []; Used terms: bytes, n