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Proof step 4 from proof fix-butlast (previous step)

¬ # bytes < n + 1 ⊦ fix(n, bytes.butlast) = fix(n + 1, bytes).butlast, n = 0, # bytes = 1, bytes = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
n < # bytes ⊦ bytes = [], # bytes = 1, n = 0, fix(n, bytes.butlast) = fix(n + 1, bytes).butlast

Rule argument

Additional information

Used simplifier rules: ⊦ # bytes = 0 ↔ bytes = [];% ⊦ m < n → n ≠ 0; (forward)% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m < n + 1 ↔ ¬ n < m;