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Proof step 10 from proof fix-last (previous step)

# bytes ≥ n ⊦ bytes = [], n = 0, lastn(n, bytes).last = bytes.last

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
n ≤ # bytes ⊦ bytes = [], n = 0, lastn(n, bytes).last = bytes.last

Rule argument

Additional information

Used simplifier rules: ⊦ n ≥ m ↔ m ≤ n;