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Proof step 11 from proof fix-value (previous step)

0 ≤ bytes2int(bytes), # bytes < n ⊦ bytes = [], bytes2int(mklist(i2b(0), n - # bytes) + bytes) = bytes2int(bytes), # bytes = n

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 12:
n = n0 + # bytes ∧ # bytes ≤ n, 0 ≤ bytes2int(bytes), # bytes < n ⊦ bytes = [], bytes2int(mklist(i2b(0), n0) + bytes) = bytes2int(bytes), # bytes = n

Rule argument

seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [n, # bytes, n0] rotate: T spec: nat inst: name: elim-sub

Additional information

Used simplifier rules: ⊦ ¬ m ≤ n ↔ n < m;% ⊦ m < n → ¬ n < m;%n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: n, # bytes, n0