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Proof step 22 from proof fix-value (previous step)

0 ≤ bits2int(bytes2bits(bytes)) ⊦ bytes = [], n0 = 0, bytes = [], bits2uint(bytes2bits(bytes)) = bits2int(bytes2bits(bytes))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
0 ≤ bits2int(bytes2bits(bytes)) ⊦ n0 = 0, bytes = [], bits2uint(bytes2bits(bytes)) = bits2int(bytes2bits(bytes))

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)