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Proof step 7 from proof fix-value (previous step)

¬(# bytes < n ∧ bytes2int(bytes) < 0), # bytes < n ⊦ # bytes = n, bytes2int(fix(n, bytes)) = bytes2int(bytes), bytes = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
# bytes < n, 0 ≤ bytes2int(bytes) ⊦ # bytes = n, bytes2int(fix(n, bytes)) = bytes2int(bytes), bytes = []

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ m < n → ¬ n < m;% ⊦ m ≠ n → (¬ m < n ↔ n < m);