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Proof step 10 from proof int2bytes-butlast (previous step)

i < 128 ∨ 256 ≤ i, i < ~128 ∨ 128 ≤ i, i < ~128 ∨ 128 ≤ i ⊦ (¬ i ≤ ~256 ∧ ¬ ~128 ≤ i ⊃ i2b(~1) ' + i2b(i) ' ;(¬ ~256 ≤ i ∧ i % 256 = 0 ⊃ int2bytes(i / 256) + i2b(i % 256) ' ;(¬ ~256 ≤ i ∧ i % 256 ≠ 0 ⊃ int2bytes(i / 256 - 1) + i2b(i % 256) ';int2bytes(i / 256) + i2b(i % 256) ') ) ) .butlast = int2bytes(i >> 8)

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Proof step 11:
¬ i ≤ ~256 ∧ ¬ ~128 ≤ i, i < 128 ∨ 256 ≤ i, i < ~128 ∨ 128 ≤ i, i < ~128 ∨ 128 ≤ i ⊦ (i2b(~1) ' + i2b(i) ').butlast = int2bytes(i >> 8)
Proof step 26:
i ≤ ~256 ∨ ~128 ≤ i, i < 128 ∨ 256 ≤ i, i < ~128 ∨ 128 ≤ i, i < ~128 ∨ 128 ≤ i ⊦ (¬ ~256 ≤ i ∧ i % 256 = 0 ⊃ int2bytes(i / 256) + i2b(i % 256) ' ;(¬ ~256 ≤ i ∧ i % 256 ≠ 0 ⊃ int2bytes(i / 256 - 1) + i2b(i % 256) ';int2bytes(i / 256) + i2b(i % 256) ') ) .butlast = int2bytes(i >> 8)

Rule argument

pos: right 1

Proof step 10 from proof int2bytes-butlast (previous step)

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Rule argument

Additional information