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Proof step 42 from proof int2bytes-butlast (previous step)

i < 128, ~256 ≤ i ∨ i % 256 = 0, ~256 ≤ i ∨ i % 256 ≠ 0, i ≤ ~256 ∨ ~128 ≤ i, i < 128 ∨ 256 ≤ i, i < ~128 ∨ 128 ≤ i ⊦ int2bytes(i / 256) = int2bytes(i >> 8)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 43:
i < 0, i ≤ ~256, i = ~256 ∨ i % 256 ≠ 0, i = ~256 ∨ i % 256 = 0 ⊦ int2bytes(i / 256) = int2bytes(i >> 8)

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i ≤ j;% ⊦ j ≤ i ∧ i < 0 → j < 0; (forward)% ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward)% ⊦ i ≤ j → (j ≤ i ↔ i = j);%j0 ≠ 0, j < j0 ⊦ i ≤ (* j) → i < (* j0);%j0 ≠ 0, j < j0 ⊦ i < (* j) → i < (* j0);% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);%j0 ≠ 0, j ≤ j0 ⊦ i < (* j) → i < (* j0);