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Proof step 48 from proof int2bytes-butlast (previous step)

256 ≤ i, 0 < i, 0 ≤ i ⊦ int2bytes(i / 256) = int2bytes(i >> 8)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 49:
⊦ 0 ≤ i ∧ 8 ≤ j → i >> j = i / 256 >> (j - 8)

Rule argument

seq: ⊦ 0 ≤ i ∧ 8 ≤ j → i >> j = i / 256 >> (j - 8) subst: [j, i] → [8, i] rotate: F spec: intops inst: name: shiftright-rec-8

Additional information

Used simplifier rules: ⊦ i >> 0 = i;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < j → ¬ j < i; Used terms: 8, i