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Proof step 8 from proof int2bytes-butlast (previous step)

0 ≤ i, 0 < i, 128 ≤ i, i < 256 ⊦ i >> 8 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ 0 ≤ i → i >> j = i / 2 ^ abs(j)

Rule argument

seq: ⊦ 0 ≤ i → i >> j = i / 2 ^ abs(j) subst: [j, i] → [8, i] rotate: F spec: intops inst: name: shiftright-pos-div-01

Additional information

Used simplifier rules: 0 < j ⊦ 0 ≤ i ∧ i < j → i / (* j) = 0; Used terms: 8, i