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Proof step 1 from proof int2bytes-byte-neg (conclusion)

⊦ ~256 < i ∧ i < ~128 → int2bytes(i) = i2b(~1) ' + i2b(i) '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
~256 < i, i < ~128, i < 0 ⊦ int2bytes(i) = i2b(~1) ' + i2b(i) '

Rule argument

Additional information

Used simplifier rules: ⊦ i < (* j) ∧ j < 0 → i < 0; (forward)