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Proof step 21 from proof int2bytes-byte-neg (previous step)

0 < 1, ~256 < i, i < ~128, i < 0, # int2bits(i) ≤ 9 ⊦ i2b(bits2int(restn(1 -1, int2bits(i).rest))) = i2b(i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
~256 < i, i < ~128, i < 0, # int2bits(i) ≤ 9 ⊦ i2b(bits2int(int2bits(i).rest)) = i2b(i)

Rule argument

Additional information

Used simplifier rules: ⊦ restn(0, bits) = bits;