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Proof step 25 from proof int2bytes-byte-neg (previous step)

~256 < i, i < ~128, i < 0, # int2bits(i) ≤ 9 ⊦ i2b(i + 2 ^ (n→i(# int2bits(i)) - 1)) = i2b(i)

User applied rule cut formula

And obtained the following new goals

Proof step 26:
# int2bits(i) = 9, ~256 < i, i < ~128, i < 0, # int2bits(i) ≤ 9 ⊦ i2b(i + 2 ^ (n→i(# int2bits(i)) - 1)) = i2b(i)
Proof step 27:
~256 < i, i < ~128, i < 0, # int2bits(i) ≤ 9 ⊦ # int2bits(i) = 9, i2b(i + 2 ^ (n→i(# int2bits(i)) - 1)) = i2b(i)

Rule argument

fma: # int2bits(i) = 9

Additional information

Used formulas: # int2bits(i) = 9