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Proof step 28 from proof int2bytes-byte-neg (previous step)

# int2bits(i) < 9, i < 0, i < ~128, ~256 < i ⊦ i2b(i + 2 ^ (n→i(# int2bits(i)) - 1)) = i2b(i), # int2bits(i) = 9

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 29:
⊦ i < ~1 → (# int2bits(i) < m ↔ 0 ≤ i + 2 ^ (n→i(m) - 2))

Rule argument

seq: ⊦ i < ~1 → (# int2bits(i) < m ↔ 0 ≤ i + 2 ^ (n→i(m) - 2)) subst: [m, i] → [9, i] rotate: F spec: int2bits inst: name: int2bits-lslen-03

Additional information

Used simplifier rules: j0 ≠ 0, j < j0 ⊦ i < (* j) → i < (* j0);% ⊦ (* j) ≤ i0 + (* j0) ↔ j - j0 ≤ i0;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used terms: 9, i