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Proof step 30 from proof int2bytes-byte-neg (previous step)

~256 < i, i < ~128, i < 0 ⊦ # int2bits(i) = 9, bits2bytes(int2bits(i)) = i2b(~1) ' + i2b(i) '

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 31:
⊦ j < 0 ∧ 1 < n → (# int2bits(j) = n ↔ ~(2 ^ (n→i(n) - 1)) ≤ j ∧ j < ~(2 ^ (n→i(n) - 2)))

Rule argument

seq: ⊦ j < 0 ∧ 1 < n → ( # int2bits(j) = n ↔ ~(2 ^ (n→i(n) - 1)) ≤ j ∧ j < ~(2 ^ (n→i(n) - 2))) subst: [n, j] → [9, i] rotate: F spec: int2bits inst: name: int2bits-leneq-neg

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < j → ¬ j < i;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false); Used terms: 9, i