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Proof step 7 from proof int2bytes-byte-neg (
previous step
)
¬(# int2bits(i) % 8 ≠ 0 ∧ 8 < # int2bits(i)), # int2bits(i) = 9, ~256 < i, i < ~128, i < 0 ⊦ bits2bytes(int2bits(i)) = i2b(~1) ' + i2b(i) '
User applied rule insert equation
And closed the goal!
Rule argument
pos: left 2 flags: discard
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