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Proof step 8 from proof int2bytes-byte-neg (previous step)

# int2bits(i) % 8 ≠ 0 ∧ 8 < # int2bits(i), # int2bits(i) = 9, ~256 < i, i < ~128, i < 0 ⊦ bits2bytes(firstn(# int2bits(i) % 8, int2bits(i))) + bits2bytes(restn(# int2bits(i) % 8, int2bits(i))) = i2b(~1) ' + i2b(i) '

User applied rule insert equation

And obtained the following new goals

Proof step 9:
9 % 8 ≠ 0 ∧ 8 < 9, ~256 < i, i < ~128, i < 0 ⊦ bits2bytes(firstn(9 % 8, int2bits(i))) + bits2bytes(restn(9 % 8, int2bits(i))) = i2b(~1) ' + i2b(i) '

Rule argument

pos: left 2 flags: discard

Proof step 8 from proof int2bytes-byte-neg (previous step)

User applied rule insert equation

And obtained the following new goals

Rule argument

Additional information