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Proof step 12 from proof int2bytes-byte (previous step)

# int2bits(i) = n0 + 8, i < 128, ~128 ≤ i ⊦ n0 = 0, bits2bytes(firstn(n0, int2bits(i))) + i2b(bits2int(lastn(8, int2bits(i)))) ' = i2b(i) '

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int2bits inst: name: int2bits-leneq-pos seq: ⊦ 0 ≤ j ∧ 1 < n → ( # int2bits(j) = n ↔ 2 ^ (n→i(n) - 2) ≤ j ∧ j < 2 ^ (n→i(n) - 1)) subst: [n, j] → [n0 + 8, i] flags: rewrite

Additional information

Used terms: n0 + 8, i