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Proof step 2 from proof int2bytes-byte (previous step)

~128 ≤ i, i < 128 ⊦ int2bytes(i) = i2b(i) '

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ int2bytes(i) = bits2bytes(int2bits(i))
Proof step 4:
~128 ≤ i, i < 128 ⊦ bits2bytes(int2bits(i)) = i2b(i) '

Rule argument

spec: bytes inst: name: int2bytes seq: ⊦ int2bytes(i) = bits2bytes(int2bits(i)) subst: [i] → [i] flags: rewrite, current

Additional information

Used terms: i