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Proof step 10 from proof int2bytes-bytes2int-length-01 (previous step)

¬(# sgn(bytes2bits(bytes)) % 8 = 0 ∧ sgn(bytes2bits(bytes)) ≠ []), # bytes < # bits2bytes(sgn(bytes2bits(bytes))) ⊦ bytes = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
# bytes < # bits2bytes(sgn(bytes2bits(bytes))) ⊦ bytes = [], # sgn(bytes2bits(bytes)) % 8 = 0

Rule argument

Additional information

Used simplifier rules: bytes2bits-empty-01: ⊦ bytes2bits(bytes) = [] ↔ bytes = [];%sgn-empty-01: ⊦ sgn(bits) = [] ↔ bits = []; from specification bitopsaux