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Proof step 13 from proof int2bytes-bytes2int-length-01 (previous step)

# sgn(bytes2bits(bytes)) % 8 ≠ 0, # bytes < # sgn(bytes2bits(bytes)) / 8 + 1 ⊦ bytes = [], # sgn(bytes2bits(bytes)) % 8 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
# bytes ≤ # sgn(bytes2bits(bytes)) / 8 ⊦ bytes = [], # sgn(bytes2bits(bytes)) % 8 = 0

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%lels: ⊦ ¬ m < n ↔ n ≤ m; from specification nat%s: ⊦ m < n + 1 ↔ ¬ n < m; from specification nat-basic2