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Proof step 16 from proof int2bytes-bytes2int-length-01 (previous step)

¬ # bytes2bits(bytes) < # sgn(bytes2bits(bytes)), # bytes ≤ # sgn(bytes2bits(bytes)) / 8 ⊦ bytes = [], # sgn(bytes2bits(bytes)) % 8 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
# bytes ≤ # sgn(bytes2bits(bytes)) / 8, # sgn(bytes2bits(bytes)) ≤ 8 * # bytes ⊦ bytes = [], # sgn(bytes2bits(bytes)) % 8 = 0

Rule argument

Additional information

Used simplifier rules: bytes2bits-length: ⊦ # bytes2bits(bytes) = i→n(8) * # bytes;%lels: ⊦ ¬ m < n ↔ n ≤ m; from specification nat