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Proof step 18 from proof int2bytes-bytes2int-length-01 (previous step)

# sgn(bytes2bits(bytes)) % 8 = 0 ∧ sgn(bytes2bits(bytes)) ≠ [], # bytes < # sgn(bytes2bits(bytes)) / 8 ⊦ bytes = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
# sgn(bytes2bits(bytes)) % 8 = 0, # bytes < # sgn(bytes2bits(bytes)) / 8 ⊦ bytes = []

Rule argument

Additional information

Used simplifier rules: bytes2bits-empty-01: ⊦ bytes2bits(bytes) = [] ↔ bytes = [];%f: ⊦ m < n → n ≠ 0; from specification nat-basic1%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%sgn-empty-01: ⊦ sgn(bits) = [] ↔ bits = []; from specification bitopsaux