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Proof step 21 from proof int2bytes-bytes2int-length-01 (previous step)

8 ≠ 0, ∃ n0. # sgn(bytes2bits(bytes)) = n0 * 8, # bytes < # sgn(bytes2bits(bytes)) / 8 ⊦ bytes = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
# sgn(bytes2bits(bytes)) = n * 8, # bytes < n ⊦ bytes = []

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; from specification nat-basic1%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult%mult-01: n ≠ 0 ⊦ (m * n) / n = m; from specification nat-div%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1