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Proof step 7 from proof int2bytes-bytes2int-length-01 (previous step)

# bytes < # bits2bytes(int2bits(bits2int(bytes2bits(bytes)))) ⊦ bytes = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
# bytes < # bits2bytes(sgn(bytes2bits(bytes))) ⊦ bytes = []

Rule argument

Additional information

Used simplifier rules: bytes2bits-empty-01: ⊦ bytes2bits(bytes) = [] ↔ bytes = [];%bits2bytes-empty: ⊦ bits2bytes(bits) ≠ [];%l: ⊦ # bytes = 0 ↔ bytes = []; from specification list-data[bytelist]%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%bits2bits-def: bits ≠ [] ⊦ int2bits(bits2int(bits)) = sgn(bits); from specification int2bits