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Proof step 16 from proof int2bytes-fillsgn-rec (previous step)

# int2bytes(i >> 8) < n - 1 ∧ 0 ≤ bytes2int(int2bytes(i >> 8)), # int2bytes(i >> 8) < n, # int2bytes(i >> 8) + 1 < n, 128 ≤ i, 0 ≤ i >> 8, 0 < i, 0 ≤ i ⊦ fillsgn(n, int2bytes(i >> 8) + i2b(i) ') = (mklist(i2b(0), n - 1 - # int2bytes(i >> 8)) + int2bytes(i >> 8)) + i2b(i) ', n = # int2bytes(i >> 8) + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
# int2bytes(i >> 8) < n, 128 ≤ i, 0 ≤ i >> 8, 0 < i, 0 ≤ i, # int2bytes(i >> 8) + 1 < n ⊦ fillsgn(n, int2bytes(i >> 8) + i2b(i) ') = (mklist(i2b(0), n - 1 - # int2bytes(i >> 8)) + int2bytes(i >> 8)) + i2b(i) ', n = # int2bytes(i >> 8) + 1

Rule argument

Additional information

Used simplifier rules: int2int: ⊦ bytes2int(int2bytes(i)) = i;% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;%n0 ≤ n ⊦ m < n - n0 ↔ m + n0 < n;% ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j;% ⊦ ¬ m ≤ n ↔ n < m;% ⊦ m < 1 ↔ m = 0;% ⊦ m < n → n ≠ 0;