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Proof step 2 from proof int2bytes-fillsgn-rec (previous step)

# int2bytes(i) ≤ n ⊦ fillsgn(n, int2bytes(i)) = fillsgn(n - 1, int2bytes(i >> 8)) + i2b(i) ', # int2bytes(i) = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i < ~128 ∨ 128 ≤ i → int2bytes(i) = int2bytes(i >> 8) + i2b(i)
Proof step 4:
¬(i < ~128 ∨ 128 ≤ i), # int2bytes(i) ≤ n ⊦ fillsgn(n, int2bytes(i)) = fillsgn(n - 1, int2bytes(i >> 8)) + i2b(i) ', # int2bytes(i) = 1
Proof step 7:
i < ~128 ∨ 128 ≤ i, #(int2bytes(i >> 8) + i2b(i)) ≤ n ⊦ fillsgn(n, int2bytes(i >> 8) + i2b(i)) = fillsgn(n - 1, int2bytes(i >> 8)) + i2b(i) ', #(int2bytes(i >> 8) + i2b(i)) = 1

Rule argument

name: int2bytes-rec-shift rotate: F subst: [i] → [i]

Additional information

Used terms: i