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Proof step 22 from proof int2bytes-fillsgn-rec (previous step)

int2bytes(i >> 8) + i2b(i) ' ≠ [], b2i((int2bytes(i >> 8) + i2b(i) ').first) < 0, # int2bytes(i >> 8) + 1 < n, 0 ≤ i, 0 < i, 0 ≤ i >> 8, 128 ≤ i, # int2bytes(i >> 8) < n ⊦ n = # int2bytes(i >> 8) + 1, fillsgn(n, int2bytes(i >> 8) + i2b(i) ') = (mklist(i2b(0), n - 1 - # int2bytes(i >> 8)) + int2bytes(i >> 8)) + i2b(i) '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
b2i((int2bytes(i >> 8) + i2b(i) ').first) < 0, # int2bytes(i >> 8) < n, 128 ≤ i, 0 ≤ i >> 8, 0 < i, 0 ≤ i, # int2bytes(i >> 8) + 1 < n ⊦ fillsgn(n, int2bytes(i >> 8) + i2b(i) ') = (mklist(i2b(0), n - 1 - # int2bytes(i >> 8)) + int2bytes(i >> 8)) + i2b(i) ', n = # int2bytes(i >> 8) + 1

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ bytes + by ' ≠ [];